Hope you are doing well and in good health.
I have the CW305 Artix7 xca100, with 0.5 Ohm shunt resistor.
I had this board because I am intrested to measure the power consumption of the digital design implemented on the FPGA.
My question is: first of all I am calculating the power consumed by the Artix7 using This formula:
Vshunt=(Vsupply-Vcore)=Voltage difference accross the shunt resistor.
Ishunt=Vshunt/Rshunt=Vshunt/0.5 ==> Power=Vcore*Ishunt. Noting that Vcore is just the terminal connected to the FPGA and Vsupply is the terminal connected to the power supply. Is this the correct way to calculate the power consumption?
In addition May I know please the exact amount of the Capacitance of the FPGA to get the energy using this formula E=0.5C*(Vsupply-Vcore)^2.???